document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=204863>Question 204863</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i need help on how to solve geometric series.  I have a problem that i simply cannot figure out and i would appreciate your help.  My problem is: if A to the first= -54, and r= 2/3 then wich answer is correct?<BR>\n" );
document.write( "A. -54, 36, -24, 16<BR>\n" );
document.write( "B. -54, -36, -18, -9<BR>\n" );
document.write( "C. -54, -36, -24, -16<BR>\n" );
document.write( "D. -54, -53 1/3, -52 2/3, -52<BR>\n" );
document.write( " Please show me how to solve this problem and give me the solution. thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #154615 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=154615\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if A to the first= -54, and r= 2/3 then wich answer is correct?<BR>\n" );
document.write( "A. -54, 36, -24, 16<BR>\n" );
document.write( "B. -54, -36, -18, -9<BR>\n" );
document.write( "C. -54, -36, -24, -16<BR>\n" );
document.write( "D. -54, -53 1/3, -52 2/3, -52<BR>\n" );
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document.write( "Start with -54 and multiply repeatedly by 2/3.<BR>\n" );
document.write( "-54, -36, -24, -16, -32/3, -64/9 etc.<BR>\n" );
document.write( "--------------------<BR>\n" );
document.write( "For the 1st 4 terms,<BR>\n" );
document.write( "that's C.\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );