document.write( "Question 28394: I need to solve this equation: x^(1/4)-10x^(1/8)+21=0 for x.\r
\n" ); document.write( "\n" ); document.write( "I totally forgot how to do this. My instructor mentioned something along the lines of this: t=x^(1/8) in this equation: at^2+bt+c=0\r
\n" ); document.write( "\n" ); document.write( "Still lost... Thanks!
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Algebra.Com's Answer #15461 by venugopalramana(3286)\"\" \"About 
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I need to solve this equation: x^(1/4)-10x^(1/8)+21=0 for x.
\n" ); document.write( "I totally forgot how to do this. My instructor mentioned something along the lines of this: t=x^(1/8) in this equation: at^2+bt+c=0
\n" ); document.write( "Still lost... Thanks!
\n" ); document.write( "YA PUT X^1/8=T...SO THAT...............X^1/4=(X^1/8)^2=T^2..SO WE GET
\n" ); document.write( "T^2-10T+21=0
\n" ); document.write( "T^2-3T-7T+21=0
\n" ); document.write( "T(T-3)-7(T-3)=0
\n" ); document.write( "(T-3)(T-7)=0
\n" ); document.write( "T=3 OR 7
\n" ); document.write( "SO X^1/8=3 OR 7
\n" ); document.write( "X=3^8 OR 7^8
\n" ); document.write( "
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