document.write( "Question 204816This question is from textbook Longman Mathematics for IGCSE
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document.write( ": Sophie sets off on awalk at 6km/h. Ten minutes later, her brother Dave sets off after her on his bicycle at 15km/h. How far must Dave go to catch up with Sophie? \n" );
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Algebra.Com's Answer #154593 by edjones(8007)![]() ![]() You can put this solution on YOUR website! d=st \n" ); document.write( "For sophie: 6* 1/6 = 1 km she is ahead of dave when he starts. \n" ); document.write( "Dave is traveling 9km faster than she. \n" ); document.write( "9t=1 \n" ); document.write( "t=1/9 h to catch up to her \n" ); document.write( "15 * 1/9 = 15/9 km distance dave must travel to catch up. \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |