document.write( "Question 204733: Find the equation of a st.line through (-3,2) that is perpendicular to x+3y=6. Write the equation of the st.line in standard form.
\n" ); document.write( "*So far I have X+3y=6
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\n" ); document.write( " =3y= -x+6 but according to my notes its im missing a step.
\n" ); document.write( "Can you please help.
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Algebra.Com's Answer #154556 by scott8148(6628)\"\" \"About 
You can put this solution on YOUR website!
perpendicular lines have slopes that are negative reciprocals of each other\r
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\n" ); document.write( "\n" ); document.write( "your next step is to get y by itself by dividing by 3 ___ y = -1/3 x + 2 ___ this is the slope-intercept form
\n" ); document.write( "___ the slope (m) is the coefficient of the x term ___ y = m x + b
\n" ); document.write( "___ m = -1/3\r
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\n" ); document.write( "\n" ); document.write( "so the slope of the new line is 3 (negative reciprocal of -1/3)\r
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\n" ); document.write( "\n" ); document.write( "using point-slope ___ y - 2 = 3 (x - (-3)) ___ y = 3x + 11
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