document.write( "Question 204756: Solve the system of equations, thank you
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document.write( " 3x + 4y + z = 7
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document.write( " 2y + z = 3
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document.write( "-5x + 3y + 8z = -31 \n" );
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Algebra.Com's Answer #154550 by alicealc(293)![]() ![]() ![]() You can put this solution on YOUR website! eliminate x from the 1st and 3rd equations by: \n" ); document.write( "multiply the 1st equation by 5: \n" ); document.write( "15x + 20y + 5z = 35 \n" ); document.write( "multiply the 3rd equation by 3: \n" ); document.write( "-15x + 9y + 24z = -93 \n" ); document.write( "add them up: \n" ); document.write( "15x + 20y + 5z = 35 \n" ); document.write( "-15x + 9y + 24z = -93 \n" ); document.write( "------------------------- (+) \n" ); document.write( "29y + 29z = -58 \n" ); document.write( "------------------ (divide each side by 29) \n" ); document.write( "y + z = -2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subtract the 2nd equation from the problem with this new equation: \n" ); document.write( "2y + z = 3 \n" ); document.write( "y + z = -2 \n" ); document.write( "------------- (-) \n" ); document.write( "y = 5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "substitute the value of y into 2nd equation: \n" ); document.write( "2y + z = 3 \n" ); document.write( "2*5 + z = 3 \n" ); document.write( "10+ z = 3 \n" ); document.write( "z = 3 - 10 = -7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "substitute the value of y and z into the 1st equation: \n" ); document.write( "3x + 4y + z = 7 \n" ); document.write( "3x + 4*5 + (-7) = 7 \n" ); document.write( "3x + 20 - 7 = 7 \n" ); document.write( "3x + 13 = 7 \n" ); document.write( "3x = 7 - 13 \n" ); document.write( "3x = -6 \n" ); document.write( "x = -6/3 = -2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so, x = -2, y = 5, z = -7\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |