document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=204766>Question 204766</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 3 more than twice its width. The perimeter is 48 feet. Find the width.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #154546 by </B><A HREF=/tutors/aboutme.mpl?userid=alicealc><B>alicealc(293)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=alicealc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=154546\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> rectangle's length = L<BR>\n" );
document.write( "rectangle's width = W\r<BR>\n" );
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document.write( "L = 3 + 2W<BR>\n" );
document.write( "perimeter = 48<BR>\n" );
document.write( "2L+ 2W = 48<BR>\n" );
document.write( "2(3 + 2W) + 2W = 48<BR>\n" );
document.write( "6 + 4W + 2W = 48<BR>\n" );
document.write( "6W = 48 - 6<BR>\n" );
document.write( "6W = 42<BR>\n" );
document.write( "W = 42/6 = 7\r<BR>\n" );
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document.write( "so,the width of the rectangle is 7 feet\r<BR>\n" );
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