document.write( "Question 204769: The length of a rectangle is 3 more than twice its width. The perimeter is 48 feet. Find the width. \n" ); document.write( "
Algebra.Com's Answer #154543 by lazi(15)\"\" \"About 
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L = 2W + 3
\n" ); document.write( "P = 48\r
\n" ); document.write( "\n" ); document.write( "P = 2(W + L)
\n" ); document.write( "48 = 2(w + 2W + 3)
\n" ); document.write( "48 = 2(3W + 3)
\n" ); document.write( "48 = 2 * 3(W + 1)
\n" ); document.write( "48 = 6(W + 1)
\n" ); document.write( "8 = W + 1
\n" ); document.write( "7 = W
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