document.write( "Question 204769: The length of a rectangle is 3 more than twice its width. The perimeter is 48 feet. Find the width. \n" ); document.write( "
Algebra.Com's Answer #154543 by lazi(15)![]() ![]() ![]() You can put this solution on YOUR website! L = 2W + 3 \n" ); document.write( "P = 48\r \n" ); document.write( "\n" ); document.write( "P = 2(W + L) \n" ); document.write( "48 = 2(w + 2W + 3) \n" ); document.write( "48 = 2(3W + 3) \n" ); document.write( "48 = 2 * 3(W + 1) \n" ); document.write( "48 = 6(W + 1) \n" ); document.write( "8 = W + 1 \n" ); document.write( "7 = W \n" ); document.write( " \n" ); document.write( " |