document.write( "Question 204706: ten years ago a man was 3 times as old as his son. in 6 years, he will be twice as old as his son. how old are they now? \n" ); document.write( "

Algebra.Com's Answer #154538 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Let m = man's present age
\n" ); document.write( "Let s = son's present age
\n" ); document.write( ":
\n" ); document.write( "Write an equation for each statement:
\n" ); document.write( ":
\n" ); document.write( "\"ten years ago a man was 3 times as old as his son.\"
\n" ); document.write( "m - 10 = 3(s-10)
\n" ); document.write( "m - 10 = 3s - 30
\n" ); document.write( "m = 3s - 30 + 10
\n" ); document.write( "m = 3s - 20; use for substitution below
\n" ); document.write( ":
\n" ); document.write( "\" in 6 years, he will be twice as old as his son.\"
\n" ); document.write( "m + 6 = 2(s+6)
\n" ); document.write( "m + 6 = 2s + 12
\n" ); document.write( "m = 2s + 12 - 6
\n" ); document.write( "m = 2s + 6
\n" ); document.write( ":
\n" ); document.write( " how old are they now?
\n" ); document.write( "Replace m with (3s - 20) in the above equation
\n" ); document.write( "3s - 20 = 2s + 6
\n" ); document.write( "3s - 2s = 6 + 20
\n" ); document.write( "s = 26 yrs is son's present age
\n" ); document.write( "then
\n" ); document.write( "m = 2s + 6
\n" ); document.write( "m = 2(26) + 6
\n" ); document.write( "m = 58 yrs is man's present age
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution in the statement:
\n" ); document.write( "\"ten years ago a man was 3 times as old as his son. \"
\n" ); document.write( "58 - 10 = 3(26 - 10)
\n" ); document.write( "48 = 3(16) \n" ); document.write( "

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