document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=204722>Question 204722</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two isosceles triangles have the same base length. The legs of one of the triangles are twice as long as the legs of the other. Find the lengths of the sides of both triangles if their perimeters are 23 cm and 41 cm.  \r<BR>\n" );
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document.write( "I haven't done much with this problem because whenever I try to solve I wind up with a weird number. I know that the perimeter of a triangle is P= a+b+c so it would be 41=a+b+c and 23=a+b+c but that is pretty obvious. Please help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #154514 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=154514\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For the first isosceles triangle:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%2Bb%2Bc+=+23 ALIGN=MIDDLE  ALT=\"a%2Bb%2Bc+=+23\"   DISABLED_style= \"max-width:90%; height:auto;\" > where b is the base and, as in any isosceles triangle, a = c, so we can write:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2a%2Bb+=+23 ALIGN=MIDDLE  ALT=\"2a%2Bb+=+23\"   DISABLED_style= \"max-width:90%; height:auto;\" > or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28b+=+23-2a%29 ALIGN=MIDDLE  ALT=\"highlight%28b+=+23-2a%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "For the second isosceles triangle:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2a%2Bb%2B2c+=+41 ALIGN=MIDDLE  ALT=\"2a%2Bb%2B2c+=+41\"   DISABLED_style= \"max-width:90%; height:auto;\" > where b is the base and, as in any isosceles triangle, 2a = 2c, so we can write:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4a%2Bb+=+41 ALIGN=MIDDLE  ALT=\"4a%2Bb+=+41\"   DISABLED_style= \"max-width:90%; height:auto;\" > or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28b+=+41-2a%29 ALIGN=MIDDLE  ALT=\"highlight%28b+=+41-2a%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Now the bases, b, are equal, so we can set these two equations equal:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=23-2a+=+41-4a ALIGN=MIDDLE  ALT=\"23-2a+=+41-4a\"   DISABLED_style= \"max-width:90%; height:auto;\" > Simplify and solve for a. Add 4a to both sides.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=23%2B2a+=+41 ALIGN=MIDDLE  ALT=\"23%2B2a+=+41\"   DISABLED_style= \"max-width:90%; height:auto;\" > Subtract 23 from both sides.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2a+=+18 ALIGN=MIDDLE  ALT=\"2a+=+18\"   DISABLED_style= \"max-width:90%; height:auto;\" > Divide both sides by 2.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a+=+9 ALIGN=MIDDLE  ALT=\"a+=+9\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c+=+9 ALIGN=MIDDLE  ALT=\"c+=+9\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b+=+23-2a ALIGN=MIDDLE  ALT=\"b+=+23-2a\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b+=+23-18 ALIGN=MIDDLE  ALT=\"b+=+23-18\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b+=+5 ALIGN=MIDDLE  ALT=\"b+=+5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "First triangle:<BR>\n" );
document.write( "a = 9, b = 5, and c = 9<BR>\n" );
document.write( "Second triangle:<BR>\n" );
document.write( "2a = 18, b = 5, and 2c = 18<BR>\n" );
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