document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=204722>Question 204722</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two isosceles triangles have the same base length. The legs of one of the triangles are twice as long as the legs of the other. Find the lengths of the sides of both triangles if their perimeters are 23 cm and 41 cm.  \r<BR>\n" );
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document.write( "I haven't done much with this problem because whenever I try to solve I wind up with a weird number. I know that the perimeter of a triangle is P= a+b+c so it would be 41=a+b+c and 23=a+b+c but that is pretty obvious. Please help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #154512 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=154512\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two isosceles triangles have the same base length. The legs of one of the triangles are twice as long as the legs of the other. Find the lengths of the sides of both triangles if their perimeters are 23 cm and 41 cm. <BR>\n" );
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document.write( "s = length of legs of smaller triangle<BR>\n" );
document.write( "2s = that of taller triangle<BR>\n" );
document.write( "b = base<BR>\n" );
document.write( "23 = b + 2s<BR>\n" );
document.write( "41 = b + 4s<BR>\n" );
document.write( "------------- Subtract<BR>\n" );
document.write( "-18 = -2s<BR>\n" );
document.write( "s = 9<BR>\n" );
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document.write( "b = 5 </SPAN>\n" );
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