document.write( "Question 28424: For the function y = x2 - 6x + 8, perform the following tasks:
\n" ); document.write( "a)Put the function in the form y = a(x - h)2 + k.
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\n" ); document.write( "\n" ); document.write( "b)What is the line of symmetry?
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\n" ); document.write( "\n" ); document.write( "c)Graph the function using the equation in part a. Explain why it is not necessary to plot points to graph when using y = a (x - h) 2 + k.
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\n" ); document.write( "\n" ); document.write( "d)In your own words, describe how this graph compares the graph of y = x2?
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Algebra.Com's Answer #15449 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
\"y++=++x%5E2+-+6x+%2B+8\" needs to be converted to a version that has duplicate factors. It is called \"completing the square\". To do this, we will look at just \"y++=++x%5E2+-+6x\" and see what third number we need to add to it.\r
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\n" ); document.write( "\n" ); document.write( "If i added +9 to the above equation, giving \"y++=++x%5E2+-+6x+%2B+9\", then this can be factorised as \"y=%28x-3%29%5E2\". This is the form i want. So...\r
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\n" ); document.write( "\n" ); document.write( "\"y++=++x%5E2+-+6x+%2B+8\" becomes \"y++=++x%5E2+-+6x++%2B+9+-+9+%2B+8\". Can you see that i have added in a \"+9\" and a \"-9\", so overall, the equation is unchanged...i am just messing it around a bit.\r
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\n" ); document.write( "\n" ); document.write( "\"y++=++x%5E2+-+6x++%2B+9+-+9+%2B+8\" becomes
\n" ); document.write( "\"y++=++%28x-3%29%5E2+-+9+%2B+8\" and finally
\n" ); document.write( "\"y++=++%28x-3%29%5E2+-+1\" which is
\n" ); document.write( "\"y++=++%28x-3%29%5E2+%2B+%28-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "This is the form the Q wanted. As to why? well, in this form, the 3 and the -1 tell us the position of the turning point in the quadratic..the point where the curve turns... it is at (3,-1)\r
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\n" ); document.write( "\n" ); document.write( "so the line of symmetry is x=3\r
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\n" ); document.write( "\n" ); document.write( "No need to plot the graph, we can sketch it... we know the turning point. Only other things to know are where does the curve cross the x- and y-axes?\r
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\n" ); document.write( "\n" ); document.write( "Crossing the y-axis is when x=0
\n" ); document.write( "\"y++=++x%5E2+-+6x+%2B+8\" becomes
\n" ); document.write( "\"y++=++%280%29%5E2+-+6%280%29+%2B+8\"
\n" ); document.write( "--> y = 8\r
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\n" ); document.write( "\n" ); document.write( "Crossing the x-axis is when y=0
\n" ); document.write( "\"y++=++%28x-3%29%5E2+-+1\" becomes
\n" ); document.write( "\"0++=++%28x-3%29%5E2+-+1\"
\n" ); document.write( "or \"%28x-3%29%5E2+-+1+=+0\"
\n" ); document.write( "\"%28x-3%29%5E2+=+1\"
\n" ); document.write( "\"%28x-3%29+=+sqrt%281%29+\" OR \"%28x-3%29+=+-sqrt%281%29+\"
\n" ); document.write( "x-3 = 1 OR x-3 = -1
\n" ); document.write( "--> x = 4 OR x = 2\r
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\n" ); document.write( "\n" ); document.write( "Graph is \"graph%28300%2C300%2C-3%2C6%2C-5%2C10%2Cx%5E2+-+6x+%2B+8%29\"\r
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\n" ); document.write( "\n" ); document.write( "Compares to \"y=x%5E2\" in the fact that it is the same curve just moved... how many units to the right? How many units down? You say.\r
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\n" ); document.write( "\n" ); document.write( "jon.
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