document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=204694>Question 204694</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi ther thanks again ur a great helppin hand .Here is the question-<BR>\n" );
document.write( "the volume of a sphere is given by V=4/3TTR^3where R= the radius of the sphere. If the radius is decreased by 25%, find the change in the volume. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #154483 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=154483\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the volume of a sphere is given by V=4/3TTR^3where R= the radius of the sphere. If the radius is decreased by 25%, find the change in the volume.<BR>\n" );
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document.write( "Original volume:<BR>\n" );
document.write( "V=(4/3)(pi)R^3<BR>\n" );
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document.write( "If radius = R - .25R = (3/4)R<BR>\n" );
document.write( "V=(4/3)(pi)[(3/4)R]^3<BR>\n" );
document.write( "V=(3/4)^3(4/3)(pi)R^3<BR>\n" );
document.write( "V=(27/64)(4/3)(pi)R^3<BR>\n" );
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document.write( "Comparing the original to the one above, we find that the change in volume will be 27/64 of the original volume </SPAN>\n" );
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