document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=204531>Question 204531</A>: <I><SPAN STYLE=\"word-break: break-all;\"> need help urgent!\r<BR>\n" );
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document.write( "1. It takes jun thrice the number of days it takes Peter to mow a lawn. When the two boys work together, the job is completed in three days. How long does it take each boy to do the job alone? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #154431 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=154431\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1. It takes jun thrice the number of days it takes Peter to mow a lawn. When the two boys work together, the job is completed in three days. How long does it take each boy to do the job alone?<BR>\n" );
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document.write( "It takes Jun 3x # of days to do the job, and Peter x days.<BR>\n" );
document.write( "So, Peter does 1/x of the job per day, and Jun does 1/3x of the job.<BR>\n" );
document.write( "Working together, they do the sum, 1/x + 1/3x per day.<BR>\n" );
document.write( "1/x + 1/3x = 4/3x per day.<BR>\n" );
document.write( "4/3x jobs per day --> 3x/4 days to do the job together.<BR>\n" );
document.write( "3x/4 = 3<BR>\n" );
document.write( "3x = 12<BR>\n" );
document.write( "x = 4<BR>\n" );
document.write( "It takes Peter 4 days.<BR>\n" );
document.write( "It takes Jun 12 days. </SPAN>\n" );
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