document.write( "Question 204633: Solve for real values of x.\r
\n" ); document.write( "\n" ); document.write( "absolutevalue(x-3) = 3-x\r
\n" ); document.write( "\n" ); document.write( "I know to set the absolute value up to equal a positive and negative possiblity and so that makes
\n" ); document.write( "x-3 = 3-x and x-3 = -3+x
\n" ); document.write( "For the first I got x = 3 but the second I got 0 = 0 and that's where I am confused. Did I do something wrong? \n" ); document.write( "

Algebra.Com's Answer #154430 by Edwin McCravy(20086) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "Let's use the principle , to replace\r\n" );
document.write( "the left side:\r\n" );
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document.write( "Now we use the principle that  if and only if \r\n" );
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document.write( "Therefore \r\n" );
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document.write( "is true  if and only if  \r\n" );
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document.write( "Subtract 3 from both sides:\r\n" );
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document.write( "Multiply through by -1, which reverses the inequality:\r\n" );
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document.write( "Or in interval notation \r\n" );
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document.write( "The equation has infinitely many solutions.\r\n" );
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document.write( "Edwin

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