document.write( "Question 204633: Solve for real values of x.\r
\n" ); document.write( "\n" ); document.write( "absolutevalue(x-3) = 3-x\r
\n" ); document.write( "\n" ); document.write( "I know to set the absolute value up to equal a positive and negative possiblity and so that makes
\n" ); document.write( "x-3 = 3-x and x-3 = -3+x
\n" ); document.write( "For the first I got x = 3 but the second I got 0 = 0 and that's where I am confused. Did I do something wrong?
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Algebra.Com's Answer #154428 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
You have the right answers. What this means is that the right side 3-x is the EXACT same as the negative half of the absolute value (go ahead and graph to confirm). So this means that if you plug in any number less than or equal 3, you'll get 0=0. So this means that the solution set is the set of all x values less than or equal 3.\r
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