document.write( "Question 204520: Need help urgent!\r
\n" ); document.write( "\n" ); document.write( "Fourteen years ago, Jun was twice as old as Charlie. the sum of their ages now is 40. What are their present ages?
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Algebra.Com's Answer #154404 by alicealc(293)\"\" \"About 
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Jun's age = J
\n" ); document.write( "Charlie's age = C\r
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\n" ); document.write( "\n" ); document.write( "14 years ago:
\n" ); document.write( "J - 14 =2*(C-14)
\n" ); document.write( "J - 14 = 2C - 28
\n" ); document.write( "J = 2C - 28 + 14
\n" ); document.write( "J = 2C - 14\r
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\n" ); document.write( "\n" ); document.write( "Now:
\n" ); document.write( "J + C =40
\n" ); document.write( "2C - 14 + C =40
\n" ); document.write( "3C - 14 = 40
\n" ); document.write( "3C = 40 + 14
\n" ); document.write( "3C = 54
\n" ); document.write( "C = 54/3 = 18
\n" ); document.write( "J = 40 - C = 40 - 18 = 22\r
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\n" ); document.write( "\n" ); document.write( "So Jun's age now is 22 years old, Charlie's age now is 18 years old\r
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