document.write( "Question 204520: Need help urgent!\r
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document.write( "Fourteen years ago, Jun was twice as old as Charlie. the sum of their ages now is 40. What are their present ages? \n" );
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Algebra.Com's Answer #154404 by alicealc(293)![]() ![]() ![]() You can put this solution on YOUR website! Jun's age = J \n" ); document.write( "Charlie's age = C\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "14 years ago: \n" ); document.write( "J - 14 =2*(C-14) \n" ); document.write( "J - 14 = 2C - 28 \n" ); document.write( "J = 2C - 28 + 14 \n" ); document.write( "J = 2C - 14\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now: \n" ); document.write( "J + C =40 \n" ); document.write( "2C - 14 + C =40 \n" ); document.write( "3C - 14 = 40 \n" ); document.write( "3C = 40 + 14 \n" ); document.write( "3C = 54 \n" ); document.write( "C = 54/3 = 18 \n" ); document.write( "J = 40 - C = 40 - 18 = 22\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So Jun's age now is 22 years old, Charlie's age now is 18 years old\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |