document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=204548>Question 204548</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Using the simultaneous equation method, find the values of x and y which satisfy the following equations:\r<BR>\n" );
document.write( "\n" );
document.write( "3x+2y=22<BR>\n" );
document.write( "2x+3y=23 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #154400 by </B><A HREF=/tutors/aboutme.mpl?userid=alicealc><B>alicealc(293)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=alicealc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=154400\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> multiply the first equation by 2:<BR>\n" );
document.write( "6x + 4y = 44<BR>\n" );
document.write( "multiply the second equation by 3:<BR>\n" );
document.write( "6x + 9y = 69\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "use the elimination process,subtract the first equation by the second equation:<BR>\n" );
document.write( "6x + 4y = 44<BR>\n" );
document.write( "6x + 9y = 69<BR>\n" );
document.write( "------------ (-)<BR>\n" );
document.write( "-5y =-25<BR>\n" );
document.write( "y = (-25)/(-5) = 5\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "substitute the y value to the first or second equation (here, I use the first):<BR>\n" );
document.write( "6x + 4*5 =44<BR>\n" );
document.write( "6x + 20= 44<BR>\n" );
document.write( "6x = 44 - 20<BR>\n" );
document.write( "6x = 24<BR>\n" );
document.write( "x = 24/6 = 4<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );