document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=28415>Question 28415</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the trig. ratio of the following<BR>\n" );
document.write( "cot 180(degrees)<BR>\n" );
document.write( "csc -270(degrees)<BR>\n" );
document.write( "sec 720(degrees) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15440 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15440\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> cot 180(degrees)=COT(180-0)=-COT(0)=-1/TAN(0)=-1/0=-INFINITY<BR>\n" );
document.write( "csc -270(degrees)=COSEC(180+90)=-COSEC(90)=-1/SIN(90)=-1<BR>\n" );
document.write( "sec 720(degrees)=SEC(360*2+0)=SEC(0)=1/COS(0)=1/1=1 </SPAN>\n" );
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