document.write( "Question 204536: I have been having a really hard problem with these logs\r
\n" ); document.write( "\n" ); document.write( "1. Log base 8 X=1/3\r
\n" ); document.write( "\n" ); document.write( "2. Log e^x^2=125\r
\n" ); document.write( "\n" ); document.write( "3. Solve for X: Log(5-2x)=log (3x+1)\r
\n" ); document.write( "\n" ); document.write( "4. Solve for X: Log(x+1)-Log(x-1)=1 \n" ); document.write( "
Algebra.Com's Answer #154398 by nerdybill(7384)\"\" \"About 
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1. Log base 8 X=1/3
\n" ); document.write( "x = 8^(1/3)
\n" ); document.write( "x = 2
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\n" ); document.write( "2. Log e^x^2=125
\n" ); document.write( "x^2 = ln(125)
\n" ); document.write( "x^2 = 4.8283
\n" ); document.write( "x = 2.197
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\n" ); document.write( "3. Solve for X: Log(5-2x)=log (3x+1)
\n" ); document.write( "5-2x = 3x+1
\n" ); document.write( "5 = 5x+1
\n" ); document.write( "4 = 5x
\n" ); document.write( "4/5 = x
\n" ); document.write( "0.8 = x
\n" ); document.write( ".
\n" ); document.write( "4. Solve for X: Log(x+1)-Log(x-1)=1
\n" ); document.write( "Log[(x+1)/(x-1)]=1
\n" ); document.write( "(x+1)/(x-1)= 10^1
\n" ); document.write( "(x+1)/(x-1)= 10
\n" ); document.write( "(x+1) = 10(x-1)
\n" ); document.write( "x+1 = 10x-10
\n" ); document.write( "1 = 9x-10
\n" ); document.write( "11 = 9x
\n" ); document.write( "11/9 = x
\n" ); document.write( "1.222 = x\r
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