document.write( "Question 204547: Mike's age is 3/4 of Mary's age. In 5 yrs, Mike's age will be 7/9 Mary's age. How old is Mike now? \n" ); document.write( "
Algebra.Com's Answer #154391 by alicealc(293)![]() ![]() ![]() You can put this solution on YOUR website! Mike's age = A \n" ); document.write( "Mary's age = B\r \n" ); document.write( "\n" ); document.write( "A = 3/4 * B \n" ); document.write( "In 5 years: \n" ); document.write( "A + 5 = 7/9 * (B + 5) \n" ); document.write( "3/4 * B + 5 = 7/9 * B + 35/9 \n" ); document.write( "3/4 * B - 7/9 * B = 35/9 - 5 \n" ); document.write( "(27/36 - 28/36) * B = 35/9 - 45/9 \n" ); document.write( "-1/36 * B = -10/9 \n" ); document.write( "B = -10/9 * -36/1 \n" ); document.write( "B = 360/9 = 40 \n" ); document.write( "A = 3/4 * 40 = 30\r \n" ); document.write( "\n" ); document.write( "So, Mike's age now is 30 years old \n" ); document.write( " \n" ); document.write( " |