document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=28413>Question 28413</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 4-7x=1-6x\r<BR>\n" );
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document.write( "thanks\r<BR>\n" );
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document.write( "Creig </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15439 by </B><A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><B>sdmmadam@yahoo.com(530)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15439\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4-7x=1-6x   ----(1)<BR>\n" );
document.write( "(-1+4)-7x+7x = (-1+1)-6x +7x  [(adding (-1) from the left and 7x from the right to both the sides.]<BR>\n" );
document.write( "3+0 = 0+x  (using additive inverse law on the left and on the right)<BR>\n" );
document.write( "3= x<BR>\n" );
document.write( "That is x= 3<BR>\n" );
document.write( "Verification: x = 3 in (1)<BR>\n" );
document.write( "LHS = 4-7x = 4-7X3 = 4-21 = -17<BR>\n" );
document.write( "RHS = 1-6x = 1-6X3 = 1-18 = -17 = LHS<BR>\n" );
document.write( "Therefore our value x= 3 is right. </SPAN>\n" );
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