document.write( "Question 204498: $\"sqrt%283x%29+-+sqrt%283x-5%29+=+1\"$
\n" ); document.write( "x = ? \n" ); document.write( "

Algebra.Com's Answer #154376 by alicealc(293) $\"\"$ $\"About$

You can put this solution on YOUR website!
square both sides of the equation
\n" ); document.write( " $\"sqrt%283x%29+-+sqrt%283x-5%29+=+1\"$
\n" ); document.write( " $\"%28sqrt%283x%29+-+sqrt%283x-5%29%29%5E2+=+%281%29%5E2\"$
\n" ); document.write( " $\"3x+-+2%2Asqrt%283x%2A%283x-5%29%29+%2B+3x+-+5+=+1\"$
\n" ); document.write( " $\"3x+%2B+3x+-+5+-+1+=+2%2Asqrt%283x%2A%283x-5%29%29\"$
\n" ); document.write( " $\"6x+-+6+=+2%2Asqrt%283x%2A%283x-5%29%29\"$ \r
\n" ); document.write( "\n" ); document.write( "square them again:
\n" ); document.write( " $\"%286x+-+6%29%5E2+=+%282%2Asqrt%283x%2A%283x-5%29%29%29%5E2\"$
\n" ); document.write( " $\"36x%5E2+-+72x+%2B+36+=+4%2A3x%2A%283x-5%29\"$
\n" ); document.write( " $\"36x%5E2+-+72x+%2B+36+=+36x%5E2+-+60x\"$
\n" ); document.write( " $\"36x%5E2+-+72x+%2B+36+-+36x%5E2+%2B+60x+=+0\"$
\n" ); document.write( " $\"-12x+%2B+36+=+0\"$ \r
\n" ); document.write( "\n" ); document.write( "12x = 36
\n" ); document.write( "x = 36/12 = 3\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );