document.write( "Question 204443: hi can you plzz help me with this question...thanks!
\n" ); document.write( "The path of a basketball shot can be modeled by the equation h = -0.09dē + 0.9d + 2 where h is the height of the basketball, in metres, and d is the horizontal distance of the ball from the player, in metres.\r
\n" ); document.write( "\n" ); document.write( "a) What is the maximum height reached by the ball?\r
\n" ); document.write( "\n" ); document.write( "b) What is the horizontal distance of the ball from the player when it reaches its maximum height?\r
\n" ); document.write( "\n" ); document.write( "c) How far from the floor is the ball when the player releases it?
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Algebra.Com's Answer #154370 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Starting with:
\n" ); document.write( "\"h%28d%29+=+-0.09d%5E2%2B0.9d%2B2\"
\n" ); document.write( "a) The maximum h can be found at the vertex of the parabola at:
\n" ); document.write( "\"d+=+%28-0.9%29%2F2%28-0.09%29\"
\n" ); document.write( "\"d+=+5\" Now substitute this value of d into the given equation and solve for h.
\n" ); document.write( "\"h%285%29+=+0.09%285%29%5E2%2B0.9%285%29%2B2\"
\n" ); document.write( "\"h%285%29+=+4.25\"
\n" ); document.write( "The maximum height is 4.25 metres.
\n" ); document.write( "b) The distance d when the ball has reached a height of 4.25 metres is:
\n" ); document.write( "\"4.25+=+-0.09d%5E2%2B0.9d%2B2\" Subtract 4.25 from both sides.
\n" ); document.write( "\"-.09d%5E2%2B0.9d-2.25+=+0\" Solve using the quadratic formula:\"x+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a\" where: a = -0.09, b = 0.9, and c = 2.25 and instead of x in the formula, we want to use d, so...
\n" ); document.write( "\"d+=+%28-0.9%2B-sqrt%280.9%5E2-4%28-0.09%29%282.25%29%29%29%2F2%28-0.09%29\"
\n" ); document.write( "\"d+=+%28-0.9%2B-sqrt%280.81-%28-0.81%29%29%29%2F%28-0.18%29\"
\n" ); document.write( "\"d+=+%28-0.9%2B-sqrt%281.62%29%29%2F%28-0.18%29\"
\n" ); document.write( "\"d+=+5\"metres.
\n" ); document.write( "c) From the original equation, the ball is 2 metres from the floor when the player releases it.
\n" ); document.write( "The general form of the equation for the height (h) an object propelled upward with an initial velocity \"v%5B0%5D\" from an initial height of \"h%5B0%5D\" is:
\n" ); document.write( "\"h%28t%29+=+-16t%5E2%2Bv%5B0%5Dt%2Bh%5B0%5D\" and \"h%5B0%5D\" = 2.
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