document.write( "Question 204444: 1. A rectangular field is to be enclosed by 600m of fence. What dimensions will give the maximum area? What is the maximum area?\r
\n" ); document.write( "\n" ); document.write( "2. The captain of a riverboat charges $36 per person including lunch. The cruise averages 300 customers a day. The captain is considering increasing the price. A survey of the customers indicates that for every $2 increase, there would be 10 fewer customers. What increase in price would maximize the revenue?
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Algebra.Com's Answer #154352 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "The perimeter of a rectangle is given by:\r
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\n" ); document.write( "\n" ); document.write( "which can be restated as:\r
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\n" ); document.write( "\n" ); document.write( "The area of a rectangle is given by:\r
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\n" ); document.write( "\n" ); document.write( "Substituting:\r
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\n" ); document.write( "\n" ); document.write( "This function has an extremum where the first derivative is equal to zero:\r
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\n" ); document.write( "\n" ); document.write( "Setting the first derivative equal to zero:\r
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\n" ); document.write( "\n" ); document.write( "This extremum is a maximum if the value of the 2nd derivative is negative.\r
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\n" ); document.write( "\n" ); document.write( "Which is negative for all values of the independent variable, hence the extremum is a maximum.\r
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\n" ); document.write( "\n" ); document.write( "In order for the width to be one fourth of the perimeter, the length must also be one-fourth of the perimeter. That is to say, the maximum area for a rectangle with a given perimeter is achieved when the rectangle is a square with side measure of one-fourth of the perimeter.\r
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\n" ); document.write( "\n" ); document.write( "Let represent the price of one fare. Then the revenue function is the number of passengers times the price of a fare. The price of one fare minus 36, quantity divided by 2 is the number of $2 increases to the price. So:\r
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\n" ); document.write( "\n" ); document.write( "First derivative:\r
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\n" ); document.write( "\n" ); document.write( "Set equal to zero:\r
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\n" ); document.write( "\n" ); document.write( "Second derivative:\r
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\n" ); document.write( "\n" ); document.write( "Hence extreme point is a maximum.\r
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