document.write( "Question 28414: Please can someone help me solve this problem
\n" ); document.write( "cot A=(3/4) and its in the 3rd quad. find the remaining ratios sin,cos,tan,csc,sec
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Please can someone help me solve this problem
\n" ); document.write( "cot A=(3/4) and its in the 3rd quad. find the remaining ratios sin,cos,tan,csc,sec
\n" ); document.write( "Consider cotA = 3/4
\n" ); document.write( "Draw a rough sketch of a right angled triangle ABC say with angle C= 90 degrees
\n" ); document.write( "If the side opposite to angle A that is if BC= (4x) and the side adjacent to angle A that is AC= (3x), then tan A = 4/3 and cot A = 3/4
\n" ); document.write( "A is an angle in the 3rd quadrant and hence here tanA and cotA are positive.
\n" ); document.write( "The other four trig ratios are negative.
\n" ); document.write( "Using Pythog. theorem, AC^2 + BC^2 = AB^2 (here AB is the hypotenuse)
\n" ); document.write( "We get AB, the hypotenuse(the side opposite the right angle) = 5x
\n" ); document.write( "Write tanA = 1/cotA and get the other four ratios (numerical) from the rough sketch and attach a minus to each of the four.
\n" ); document.write( "Note: If you really understand the concept that the sides ought to be, 3x, 4x and 5x, then you may leave out x in the sense you may assume x=1 without loss of generality.
\n" ); document.write( "tanA =4/3
\n" ); document.write( "sinA= -(opp/hyp) = -4/5
\n" ); document.write( "cosecA = -(hyp/opp) = -5/4
\n" ); document.write( "cosA = -(adj/hyp) = -(3/5)
\n" ); document.write( "secA = -(hyp/adj) = -(5/3)
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