document.write( "Question 204388: The weight of an object varies inversely with the square of it's distance from the center of the earth. If an object 8000 miles from the center of the earth weighs 90 pounds, find it's weight when it is 12000 miles from the center of the earth. \n" ); document.write( "

Algebra.Com's Answer #154312 by Earlsdon(6294) $\"\"$ $\"About$

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\"The weight (W) of an object on earth varies inversely with the square of its (not it's) distance (d) from the center of the earth\" This relationship can be expressed as:
\n" ); document.write( " $\"W+=+k%2Fd%5E2\"$ where k is the constant of variation.
\n" ); document.write( "To find the value of k, we'll substitute the given values of W = 90 lbs and d = 8000 miles.
\n" ); document.write( " $\"90+=+k%2F%288000%29%5E2\"$
\n" ); document.write( " $\"k+=+90%2864000000%29\"$
\n" ); document.write( " $\"k+=+5760000000\"$
\n" ); document.write( "So our formula becomes:
\n" ); document.write( " $\"W+=+5760000000%2Fd%5E2\"$ Substitute d = 12000 miles.
\n" ); document.write( " $\"W+=+5760000000%2F%2812000%29%5E2\"$
\n" ); document.write( " $\"W+=+5760000000%2F144000000\"$
\n" ); document.write( " $\"highlight%28W+=+40%29\"$ lbs.
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