document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=28402>Question 28402</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this equation=><BR>\n" );
document.write( " -780 (degrees) in six triginometric ratio<BR>\n" );
document.write( "sin, cos tan, cot, sec, csc   \r<BR>\n" );
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document.write( "I put it on a graph and i know it goes counterclock wise since it is a (-) after this i landed in the 4th quadrant then i -360+ -360+ -60=-780(degrees) \r<BR>\n" );
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document.write( "but i don't know where to go from there or if all this work i have done is right at all. If someone could please try and help me out or guide me in the right direction I would much be appreciative </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15430 by </B><A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><B>sdmmadam@yahoo.com(530)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15430\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this equation=><BR>\n" );
document.write( " -780 (degrees) in six triginometric ratio<BR>\n" );
document.write( "sin, cos tan, cot, sec, csc   \r<BR>\n" );
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document.write( "We know that any trignometic fn of [2n(Pi)+ or minus(angle theta)] <BR>\n" );
document.write( "= + or minus the angle theta<BR>\n" );
document.write( "Pi radians = 360 degrees<BR>\n" );
document.write( "Therefore to (-780)degrees add the nearest positive number of revolutions namely two revoultions in this problem that is add 2X(360)=720 degrees<BR>\n" );
document.write( "Then (-780) + 720 = (-60)degrees.<BR>\n" );
document.write( "What is the idea?<BR>\n" );
document.write( "The idea is to bring the angle to an acute form (or in some cases obtuse form)<BR>\n" );
document.write( "numerically.<BR>\n" );
document.write( "As you have rightly understood- the position of the angle (-780) is the fourth quadrant and we are in a situation where <BR>\n" );
document.write( "any trig fn(-780) is equivalent to the same trig fn (-60)<BR>\n" );
document.write( "Therefore sin (-780 degrees) =sin(-60) -sin(60) = -(sqrt3)/2<BR>\n" );
document.write( "cos(-60)= +cos(60) = 1/2<BR>\n" );
document.write( "tan(-60)= -tan(60) = -(sqrt3)<BR>\n" );
document.write( "cosec(-60)= -cosec(60) = -(1/sin(60)) = -1/[(sqrt3)/2] = -2/(sqrt3)<BR>\n" );
document.write( "sec(-60)= +sec(60) = +(1/cos(60)) = 1/(1/2) = 2<BR>\n" );
document.write( "cot(-60)= -cot(60) = -1/(tan(60))= -1/(sqrt3)<BR>\n" );
document.write( "Note: In the fourth quadrant only the cosine and its reciprocal fn secant are positive.\r<BR>\n" );
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