document.write( "Question 204381: find the area of a rectangle with length 4 and diagonal 5. \n" ); document.write( "

Algebra.Com's Answer #154295 by Earlsdon(6294) $\"\"$ $\"About$

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Start with:
\n" ); document.write( " $\"A+=+L%2AW\"$
\n" ); document.write( "You are given the length (L = 4) but not the width (W).
\n" ); document.write( "You can find the width using the Pythagorean theorem: $\"c%5E2+=+a%5E2%2Bb%5E2\"$ where c is the hypotenuse of the right triangle (also the diagonal of the rectangle), and a is the length of the rectangle.
\n" ); document.write( "b is the width (W) which is what we need to find before we can calculate the area. So...
\n" ); document.write( " $\"5%5E2+=+4%5E2%2BW%5E2\"$
\n" ); document.write( " $\"25+=+16%2BW%5E2\"$
\n" ); document.write( " $\"W%5E2+=+25-16\"$
\n" ); document.write( " $\"W%5E2+=+9\"$
\n" ); document.write( " $\"W+=+3\"$
\n" ); document.write( "The area is:
\n" ); document.write( " $\"A+=+L%2AW\"$ Substitute L = 4 and W = 3.
\n" ); document.write( " $\"A+=+4%2A3\"$
\n" ); document.write( " $\"highlight%28A+=+12%29\"$ sq.units. \n" ); document.write( "

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