document.write( "Question 204343: can you help me solve this word problem; 1) A piece of cardboard has a length of 60cm and a width of 40cm. In order to make the cardboard into an open box, a box with no lid), a piece of length x must be cut out of each corner. \r
\n" ); document.write( "\n" ); document.write( "-Write an equation to represent each dimension of the box.
\n" ); document.write( "-Using the dimensions from part a), find the S.A and Volume of the box. (Remember that it is an open box with no lid.)
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Algebra.Com's Answer #154272 by Earlsdon(6294)\"\" \"About 
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Let L = the length of the finished box and W = is width. If h = its height, then: (The corners are assumed to be square with side = x)
\n" ); document.write( "\"L+=+60-2x\"
\n" ); document.write( "\"W+=+40-2x\" and...
\n" ); document.write( "\"h+=+x\"
\n" ); document.write( "The surface area, (4 sides plus bottom) SA (as a function of x), can be expressed as:
\n" ); document.write( "\"SA+=+2%28x%2860-2x%29%29%2B2%28x%2840-2x%29%29%2B%2860-2x%29%2840-2x%29\" Simplify.
\n" ); document.write( "\"SA+=+%282%2860x-2x%5E2%29%29%2B%282%2840x-2x%5E2%29%29%2B%282400-200x%2B4x%5E2%29\"
\n" ); document.write( "\"SA+=+120x-4x%5E2%2B80x-4x%5E2%2B2400-200x%2B4x%5E2\"
\n" ); document.write( "\"highlight%28SA+=+-4x%5E2%2B2400%29\"
\n" ); document.write( "For the volume:
\n" ); document.write( "\"V+=+L%2AW%2Ah\"
\n" ); document.write( "\"V+=+%2860-2x%29%2840-2x%29%28x%29\"
\n" ); document.write( "\"V+=+%282400-200x%2B4x%5E2%29X\"
\n" ); document.write( "\"highlight_green%28V+=+4x%5E3-200x%5E2%2B2400x%29\"
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