document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=28396>Question 28396</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Will you simplify this for me? \r<BR>\n" );
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document.write( "4y(2y^2-3y)-3y^2(y-4) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15426 by </B><A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><B>sdmmadam@yahoo.com(530)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15426\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4y(2y^2-3y)-3y^2(y-4)<BR>\n" );
document.write( "=8y^3-12y^2-3y^3+12y^2<BR>\n" );
document.write( "=8y^3+(-12y^2-3y^3)+12y^2 by additive associativity<BR>\n" );
document.write( "=8y^3+(-3y^3-12y^2)+12y^2 by additive commutativity<BR>\n" );
document.write( "=(8y^3-3y^3)-12y^2+12y^2  by additive associativity<BR>\n" );
document.write( "=5y^3+0   (using -a+a = 0 by additive inverse law)<BR>\n" );
document.write( "=5y^3<BR>\n" );
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