document.write( "Question 204300: e^xlnx how do I simplify this. thank you \n" ); document.write( "
Algebra.Com's Answer #154248 by stanbon(75887)\"\" \"About 
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e^xlnx how do I simplify this
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\n" ); document.write( "Note: e^(ln(a)) = a
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\n" ); document.write( "Therefore: e^(xlnx) = [e^(lnx)]^(x) = x^x
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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