document.write( "Question 204290: could anyone out there help me out here: how many positive real roots and how many negative roots does the problem have; f(a)=a^5-4a^2-7 (using Descartes rule of signs? \n" ); document.write( "
Algebra.Com's Answer #154234 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "First count the sign changes of \"f%28a%29=a%5E5-4a%5E2-7\"\r
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\n" ); document.write( "\n" ); document.write( "From \"a%5E5\" to \"-4a%5E2\", there is a sign change from positive to negative \r
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\n" ); document.write( "\n" ); document.write( "From \"-4a%5E2\" to \"-7\", there is no change in sign\r
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\n" ); document.write( "\n" ); document.write( "So there is 1 sign change for the expression \"f%28a%29=a%5E5-4a%5E2-7\". \r
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\n" ); document.write( "\n" ); document.write( "So there is 1 positive real zero\r
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\n" ); document.write( "\n" ); document.write( "\"f%28-a%29=%28-a%29%5E5-4%28-a%29%5E2-7\" Now let's replace each \"a\" with \"-a\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%28-a%29=-a%5E5-4a%5E2-7\" Simplify. Note: only the terms with odd exponents will have a sign change.\r
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\n" ); document.write( "\n" ); document.write( "Now let's count the sign changes of \"f%28-a%29=-a%5E5-4a%5E2-7\"\r
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\n" ); document.write( "\n" ); document.write( "From \"-a%5E5\" to \"-4a%5E2\", there is no change in sign\r
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\n" ); document.write( "\n" ); document.write( "From \"-4a%5E2\" to \"-7\", there is no change in sign\r
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\n" ); document.write( "\n" ); document.write( "So there are no sign changes for the expression \"f%28-a%29=-a%5E5-4a%5E2-7\"\r
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\n" ); document.write( "\n" ); document.write( "So there are 0 negative real zeros\r
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\n" ); document.write( "\n" ); document.write( "Note: if you graph \"f%28a%29=a%5E5-4a%5E2-7\", you will find that there is indeed one positive real zero.
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