document.write( "Question 204259: A boat can travel 14 miles upstream in the same amount of time it takes to travel 21 miles downstream. If the current is 2 miles per hour, what is the speed of the boat in still water? \n" ); document.write( "
Algebra.Com's Answer #154225 by Earlsdon(6294)\"\" \"About 
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Use the distance formula:
\n" ); document.write( "\"d+=+r%2At\" where: d = distance trveled, r = rate(speed), and t = time of travel.
\n" ); document.write( "For the trip upstream (against the current of 2mph), d = 14mi. and r = speed of the boat, so you can write:
\n" ); document.write( "\"14+=+%28r-2%29%2At\" The speed of the current is subtracted from the speed of the boat going upstream.
\n" ); document.write( "For the trip downstream (with the current of 2mph), d = 21mi, and r = the speed of the boat, so you can write:
\n" ); document.write( "\"21+=+%28r%2B2%29%2At\" The time, t, is the same in both cases, so we solve both equations for t and set them equal to each other.
\n" ); document.write( "Upstream trip:
\n" ); document.write( "\"t+=+14%2F%28r-2%29\"
\n" ); document.write( "Downstream trip:
\n" ); document.write( "\"t+=+21%2F%28r%2B2%29\" Set these equal to each other.
\n" ); document.write( "\"14%2F%28r-2%29+=+21%2F%28r%2B2%29\" Solve for r, the speed of the boat in still water. Cross multiply.
\n" ); document.write( "\"14%28r%2B2%29+=+21%28r-2%29\" Simplify.
\n" ); document.write( "\"14r%2B28+=+21r-42\" Subtract 14r from both sides.
\n" ); document.write( "\"28+=+7r-42\" Add 42 to both sides.
\n" ); document.write( "\"70+=+7r\" Finally, divide both sides by 7.
\n" ); document.write( "\"r+=+10\"
\n" ); document.write( "The speed of the boat in still water is 10mph.\r
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