document.write( "Question 204257: Hey I have been having a hard time with the log's here's my three questions,
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\n" ); document.write( "1. Solve for x; log(5-2x)-log(x-1). Can you also work it out thanks\r
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\n" ); document.write( "2. Solve for x; log (x+1)-log(x-1).\r
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\n" ); document.write( "\n" ); document.write( "3. Log e^x^2=25
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Algebra.Com's Answer #154217 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
1. Solve for x; log(5-2x)=log(x-1).
\n" ); document.write( "5-2x = x-1
\n" ); document.write( "3x = 6
\n" ); document.write( "x = 2
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\n" ); document.write( "2. Solve for x; log(x+1)-log(x-1)=1.
\n" ); document.write( "log[(x+1)/(x-1)] = 1
\n" ); document.write( "(x+1)/(x-1) = 10
\n" ); document.write( "x+1 = 10x-10
\n" ); document.write( "8x = 11
\n" ); document.write( "x = 11/8
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\n" ); document.write( "3. Log e^x^2=125
\n" ); document.write( "x^2(log e) = log(125)
\n" ); document.write( "x^2 = [log(125)/log e]
\n" ); document.write( "x^2 = 4.8283
\n" ); document.write( "x = 2.1973...
\n" ); document.write( "Comment: I still think this last problem was posted incorrectly.
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\n" ); document.write( "4. log(8)x = 1/3
\n" ); document.write( "x = 8^(1/3)
\n" ); document.write( "x = 2
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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