document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=28369>Question 28369</A>: <I><SPAN STYLE=\"word-break: break-all;\"> m to the 3 over mn to the 3....multiplied by, n over m in parathesis to the 4!! please help...thank u!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15421 by </B><A HREF=/tutors/aboutme.mpl?userid=ashleygurl92><B>ashleygurl92(6)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ashleygurl92><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15421\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> m to the 3rd over mn to the 3rd times n over m in parenthesis to the 4th.\r<BR>\n" );
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document.write( "the m to the 3rd over mn to the 3rd stays the same & the n over m in parenthesis to the 4th becomes n to the 4th over m to the 4th.\r<BR>\n" );
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document.write( "then, you multiply straight across & get m to the 3rd n to the 4th over m to the 5th n to the 3rd.\r<BR>\n" );
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document.write( "then you have to simplify,<BR>\n" );
document.write( "m to the 3rd minus m to the 5th & n to the 4th minus n to the 3rd which leaves you with m to the -2nd n & you have to bring the negative to the bottom & when u do that, its not negative anymore so you get n over m to the second.\r<BR>\n" );
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document.write( "hope that wasn't too confusing,<BR>\n" );
document.write( "ashleygurl92 </SPAN>\n" );
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