document.write( "Question 204232: 8x^(4)-6x^(2)-5=0 \n" ); document.write( "
Algebra.Com's Answer #154196 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
SOlve for x:
\n" ); document.write( "You can expect to get four solutions to this \"quartic\" equation. First, rewrite the equation so as to appear like a \"quadratic\" equation in \"x%5E2\":
\n" ); document.write( "\"8%28x%5E2%29%5E2-6%28x%5E2%29-5+=+0\" Factor this \"quadratic\"equation.
\n" ); document.write( "\"%284x%5E2-5%29%282x%5E2%2B1%29+=+0\" Apply the zero product rule:
\n" ); document.write( "\"4x%5E2-5+=+0\" or \"2x%5E2%2B1+=+0\" so that...
\n" ); document.write( "\"4x%5E2+=+5\" or \"2x%5E2+=+-1\" and...
\n" ); document.write( "\"highlight%28x%5E2+=+5%2F4%29\" or \"highlight_green%28x%5E2+=+-1%2F2%29\" Now take the square root of both sides of these two intermdediate solutions.
\n" ); document.write( "\"highlight%28x+=+sqrt%285%29%2F2%29\" or \"highlight%28x+=+-sqrt%285%29%2F2%29\" or
\n" ); document.write( "\"highlight_green%28x+=+sqrt%28-1%2F2%29%29\" or \"highlight_green%28x+=+-sqrt%28-1%2F2%29%29\"
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