document.write( "Question 204201: Suppose that the width of a rectangle is 5 inches shorter than the length and that the perimeter of the rectangle is 50.
\n" ); document.write( "a) Set up an equation for the perimeter involving only L, the length of the rectangle.\r
\n" ); document.write( "\n" ); document.write( "b) Solve this equation algebraically to find the length of the rectangle. Find the width as well.
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Algebra.Com's Answer #154185 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "Let the length of the rectangle be L\r
\n" ); document.write( "\n" ); document.write( "Since its width is 5 less than its length, then width = L – 5\r
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\n" ); document.write( "\n" ); document.write( "Now, since its perimeter = 50, then 2(L) + 2(L – 5) = 50\r
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\n" ); document.write( "\n" ); document.write( "a) 2L + 2L – 10 = 50 (equation of perimeter, in terms of L, its length)\r
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\n" ); document.write( "\n" ); document.write( "b) 2L + 2L – 10 = 50
\n" ); document.write( " 4L = 60
\n" ); document.write( " L = 15\r
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\n" ); document.write( "\n" ); document.write( "Since L, or its length is \"highlight_green%2815%29\"”, then its width is (15 - 5), or \"highlight_green%2810%29\"
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