document.write( "Question 204201: Suppose that the width of a rectangle is 5 inches shorter than the length and that the perimeter of the rectangle is 50.
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document.write( "a) Set up an equation for the perimeter involving only L, the length of the rectangle.\r
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document.write( "b) Solve this equation algebraically to find the length of the rectangle. Find the width as well. \n" );
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Algebra.Com's Answer #154185 by MathTherapy(10552)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Let the length of the rectangle be L\r \n" ); document.write( "\n" ); document.write( "Since its width is 5 less than its length, then width = L – 5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, since its perimeter = 50, then 2(L) + 2(L – 5) = 50\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a) 2L + 2L – 10 = 50 (equation of perimeter, in terms of L, its length)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "b) 2L + 2L – 10 = 50 \n" ); document.write( " 4L = 60 \n" ); document.write( " L = 15\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since L, or its length is \n" ); document.write( " \n" ); document.write( " |