document.write( "Question 204198: The width of a rectangle is 4 less than twice its length. If the area of the rectangle is 183 cm^2, what is the length of the diagonal? \n" ); document.write( "
Algebra.Com's Answer #154181 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "Let the length of the rectangle be L
\n" ); document.write( "Since its width is 4 less than twice its length, then width = 2L - 4
\n" ); document.write( "Since its area = 183 cm^2, then we’’ll have: \r
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\n" ); document.write( "\n" ); document.write( "L(2L – 4) = 183
\n" ); document.write( "\"2L%5E2-4L-183+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "Using the quadratic equation: \"x=%28-b%2B-sqrt%28b%5E2-4%2Aa%2Ac%29%29%2F%282%2Aa%29\", where:\r
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\n" ); document.write( "\n" ); document.write( "a = 2 ; b = - 4 ; c = - 183, we have:\r
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\n" ); document.write( "\n" ); document.write( "\"L=%28--4%2B-sqrt%28-4%5E2-4%2A2%2A-183%29%29%2F%282%2A2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"L=%284%2B-sqrt%2816%2B1464%29%29%2F%284%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"L=%284%2B-sqrt%281480%29%29%2F%284%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"L=%284%2B38.47%29%2F4\" or \"L=%284-38.47%29%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "\"L=42.47%2F4\" or \"L=-34.47%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "L = \"highlight_green%2810.62%29\" or \"highlight_green%28-8.62%29\"\r
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\n" ); document.write( "\n" ); document.write( "Since we CANNOT have a negative measurement, we reject L = - 8.62\r
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\n" ); document.write( "\n" ); document.write( "Therefore, the length (or base) of the rectangle is 10.62 cm, and the width (or height) = 2(10.62) – 4 = 21.24 – 4 = 17.24 cm.\r
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\n" ); document.write( "\n" ); document.write( "To now find the diagonal, we use the Pythagorean formula: \"a%5E2%2Bb%5E2=c%5E2\", using the length and width as “a” & “b” and the diagonal as “c.”\r
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\n" ); document.write( "\n" ); document.write( "\"a%5E2%2Bb%5E2=c%5E2\" \r
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\n" ); document.write( "\n" ); document.write( "\"10.62%5E2%2B17.24%5E2=c%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"112.78+%2B+297.22+=+c%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"410=c%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%28410%29=c\"\r
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\n" ); document.write( "\n" ); document.write( "c, or the diagonal = \"highlight_green%2820.25%29\" cm.
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