document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=28352>Question 28352</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 4ysquard+9y-28=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15417 by </B><A HREF=/tutors/aboutme.mpl?userid=elima><B>elima(1433)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=elima><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15417\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4y%5E2 ALIGN=MIDDLE  ALT=\"4y%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >+9y-28=0<BR>\n" );
document.write( "First of all look at the second sign in the equation; it is -, so that means when you factor, one sign is - and the other is +. Now the first sign is +, so that means the larger number is going to be +.<BR>\n" );
document.write( "So begin by listing all your factors of 4, and factors of 29,<BR>\n" );
document.write( "when you do you need to decide which ones, when subtracted together the = 9;<BR>\n" );
document.write( "you should have found that they are; 4*1, and 4*7;<BR>\n" );
document.write( "(4y+7)(y+4)<BR>\n" );
document.write( "Hope you understand<BR>\n" );
document.write( "=) </SPAN>\n" );
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