document.write( "Question 204201: Suppose that the width of a rectangle is 5 inches shorter than the length and that the perimeter of the rectangle is 50.
\n" ); document.write( "a) Set up an equation for the perimeter involving only L, the length of the rectangle.\r
\n" ); document.write( "\n" ); document.write( "b) Solve this equation algebraically to find the length of the rectangle. Find the width as well.
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Algebra.Com's Answer #154166 by rfer(16322)\"\" \"About 
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let width =L=11.25
\n" ); document.write( "let length =L+5=16.25
\n" ); document.write( "2L+2L+5=50
\n" ); document.write( "4L=45
\n" ); document.write( "L=11.25
\n" ); document.write( "
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