document.write( "Question 204197: A rectangular garden is 15 ft longer than it is wide. Its area is 7600 ft^2. What are its dimensions? \n" ); document.write( "
Algebra.Com's Answer #154165 by Earlsdon(6294)\"\" \"About 
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Starting with the formula for the area of a rectangle:
\n" ); document.write( "\"A+=+L%2AW\"
\n" ); document.write( "In this problem:
\n" ); document.write( "\"L+=+W%2B15\" \"A rectangular garden is 15 feet longer than it is wide.\" and:
\n" ); document.write( "\"A+=+7600\"sq.ft. So...
\n" ); document.write( "\"7600+=+L%2AW\" Substitute L = W+15
\n" ); document.write( "\"7600+=+%28W%2B15%29%2A%28W%29\"
\n" ); document.write( "\"7600+=+W%5E2%2B15W\" Subtract 7600 from both sides.
\n" ); document.write( "\"W%5E2%2B15W-7600+=+0\" Factor this trinomial.
\n" ); document.write( "\"%28W-80%29%28W%2B95%29+=+0\" Apply the zero product rule.
\n" ); document.write( "\"W-80+=+0\" or \"W%2B95+=+0\" so that...
\n" ); document.write( "\"W+=+80\" or \"cross%28W+=+-95%29\" Discard the negative solution as the width is a positive quantity.
\n" ); document.write( "\"W+=+80\" and...
\n" ); document.write( "\"L+=+W%2B15\"
\n" ); document.write( "\"L+=+95\"
\n" ); document.write( "The length is 95 feet and the width is 80 feet.
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