document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=204192>Question 204192</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If there are 2 apples and every year the percentage of apples increase by 2%. How many apples are there in 6000 years?\r<BR>\n" );
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document.write( "For the first year the formula seems to work  2+1[2(.02)]=2.04<BR>\n" );
document.write( "For the second year, I think it should be 2.04+1[2.04(.02)]=2.0808<BR>\n" );
document.write( "because we have to take into consideration the initial increase and 2% of the initial increase for further increase.<BR>\n" );
document.write( "For the third year, 2.0808+1[2.0808(.02)]=2.122416<BR>\n" );
document.write( "And so on.\r<BR>\n" );
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document.write( "How do I go about calculating the problem without having to do it 6000 times? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #154163 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=154163\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> try this\r<BR>\n" );
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document.write( "2 * (1.02)^6000 (that's 1.02 to the 6000th power) </SPAN>\n" );
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