document.write( "Question 203964: which would have a greater change in volume, an aluminum sphere with a radius of 0.4m at 2 degrees celcius that is raised to 45 degrees celcius, or a copper cylinder of radius 0.2m height 3m at 14 degrees celcius that is raised to 35 degrees celcius? \n" ); document.write( "
Algebra.Com's Answer #154160 by RAY100(1637)\"\" \"About 
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Volume of sphere = (4/3) pi *r^3
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\n" ); document.write( "Delta V = (4/3) pi *{ (alpha) (*r)*(delta T) }^3
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\n" ); document.write( "alpha for alum = 24 * 10^-6,
\n" ); document.write( "Radius = .4 m
\n" ); document.write( "delta T = (45-2)=43 deg C
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\n" ); document.write( "Delta V = (4/3) pi * { (24*10-6) * .4 * 43)}^3 = 2.946 *10^-10
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\n" ); document.write( "Volume of Cylinder = B*h = (pi * r^2) * h
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\n" ); document.write( "Delta V = pi { (alpha)(r)(delta T)}^2 * { (alpha)(h)( delta T)}
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\n" ); document.write( "alpha copper = 17 *10^-6
\n" ); document.write( "r=.2
\n" ); document.write( "h=3
\n" ); document.write( "delta T = (35-14) = 21
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\n" ); document.write( "delta V = pi *{(17*10^-6)(.2)(21)}^2 * {(17*10^-6)(3)(21)}
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\n" ); document.write( "delta V = 1.7153 *10^-11
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\n" ); document.write( "Therefore the alum sphere has greater volume change
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\n" ); document.write( "approx 3*10^-10 vs 2*10^-11 \r
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