document.write( "Question 204167: One principle used by the ancient
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document.write( "Greeks to get shapes that are pleasing to the eye in art
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document.write( "and architecture was the Golden Rectangle. If a square
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document.write( "is removed from one end of a Golden Rectangle, as shown
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document.write( "in the figure, the sides of the remaining rectangle are
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document.write( "proportional to the original rectangle. So the length
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document.write( "and width of the original rectangle satisfy
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document.write( "L/W = W/L-W\r
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document.write( "An artist wants her painting to be in the
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document.write( "shape of a golden rectangle. If the length of the painting is
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document.write( "36 inches, then what should be the width?\r
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document.write( "So far the only thing I have is 36/w = w/36-w. I can't find an example in my book that looks like this equation. I am missing a step somewhere. \n" );
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Algebra.Com's Answer #154155 by scott8148(6628)![]() ![]() You can put this solution on YOUR website! nothing missing ___ you just need to solve the equation\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "\"cross\" multiplying ___ 36^2 - 36w = w^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "0 = w^2 + 36w - 1296 ___ use the quadratic formula to find w\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "*******************ANSWER BELOW*******************************\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "18 * [sqrt(5) - 1] \n" ); document.write( " |