document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=204113>Question 204113</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A pony is 40 jumps ahead of the horse, and takes 3 jumps while the horse takes 2 ,but 2 of the horse's jumps equal 4 of the pony's; in how many jumps while the horse catch up to the pony? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #154142 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=154142\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Key  is  the  distance  for  each  jump.  Horse  @2 =Pony@4,  or  horse  jumps  twice  as  far.<BR>\n" );
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document.write( "therefore  horse  jumps 2 times  @ twice  as  far = 4 vs Pony 3 times  @1 =4<BR>\n" );
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document.write( "In  summary,  horse  covers  a  distance  of  4,  while  pony  covers 3.<BR>\n" );
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document.write( "Pony  is  40 jumps  ahead<BR>\n" );
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document.write( "4n = 40 +3n<BR>\n" );
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document.write( "n=40,,,number  of  jumps  to  be  even<BR>\n" );
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