document.write( "Question 204170: I need help putting this word problem into equation form, can someone help me?\r
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document.write( "A business invests $8000 in a savings account for 2 years. At the beginning of the second year, an additional $2500 is invested. At the end of the second year, the account balance is $11445. What was the annual interest rate? \n" );
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Algebra.Com's Answer #154138 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A business invests $8000 in a savings account for 2 years. \n" ); document.write( " At the beginning of the second year, an additional $2500 is invested. \n" ); document.write( " At the end of the second year, the account balance is $11445. \n" ); document.write( " What was the annual interest rate? \n" ); document.write( ": \n" ); document.write( "let x = interest rate (in decimal form) \n" ); document.write( ": \n" ); document.write( "An equation for this: \n" ); document.write( ": \n" ); document.write( "(1+x)((8000(1+x))+2500)) = 11445 \n" ); document.write( ": \n" ); document.write( "(1+x)(8000 + 8000x + 2500) = 11445 \n" ); document.write( ": \n" ); document.write( "(1+x)(8000x + 10500) = 11445 \n" ); document.write( "; \n" ); document.write( "8000x + 10500 + 8000x^2 + 10500x = 11445 \n" ); document.write( ": \n" ); document.write( "8000x^2 + 8000x + 10500x + 10500 - 11445 = 0 \n" ); document.write( "Simplify divide by 5: \n" ); document.write( "8000x^2 + 18500x - 945 = 0 \n" ); document.write( ": \n" ); document.write( "1600x^2 + 3700x - 189 = 0 \n" ); document.write( ": \n" ); document.write( "Use the quadratic formula \n" ); document.write( " \n" ); document.write( "in this equation: a=1600, b=3700, c= -189 \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "The positive solution \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "x = .05; 5% is the interest rate \n" ); document.write( "; \n" ); document.write( "; \n" ); document.write( "See if this is true \n" ); document.write( "1st year: 1.05*8000 = 8400 \n" ); document.write( "Add 2500 after the 1st year = 10900 \n" ); document.write( "End of 2nd yr: 1.05(10900) = 11445 \n" ); document.write( " |