document.write( "Question 204168: Sorry if this is the wrong place for this question. \r
\n" ); document.write( "\n" ); document.write( "If there are 2 apples and every year the percentage of apples increase by 2%. How many apples are there in 6000 years?
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Algebra.Com's Answer #154128 by lazi(15)\"\" \"About 
You can put this solution on YOUR website!
starting out with 2 apples
\n" ); document.write( "every year the amount of apples increase by 2%
\n" ); document.write( "how many apples are there in 6000 years\r
\n" ); document.write( "\n" ); document.write( "2+1[2(.02)]=2.04
\n" ); document.write( "2+2[2(.02)]=2.08
\n" ); document.write( "and so on to 6000 years
\n" ); document.write( "2+6000[2(.02)]=242\r
\n" ); document.write( "\n" ); document.write( "the beginning 2 is your starting out amount.
\n" ); document.write( "6000 is your years, and 2(.02) is the amount increase per year.\r
\n" ); document.write( "\n" ); document.write( "another way of saying this is that in 6000 years the % increase is (2% * 6000) = 12000% = 12000/100\r
\n" ); document.write( "\n" ); document.write( "2+2*12000/100= 2+240=242
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