document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=204151>Question 204151</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 5)	A tennis club offers two payment options:<BR>\n" );
document.write( "Option 1:  $42 monthly fee plus $5/hour for court rental<BR>\n" );
document.write( "Option 2:  No monthly fee but $8.50/hour for court rental.<BR>\n" );
document.write( "	Let x = hours per month of court rental time. <BR>\n" );
document.write( "a)	Write a mathematical model representing the total monthly cost, C, in terms of x for the following:<BR>\n" );
document.write( "Option 1: C= 42+5x<BR>\n" );
document.write( "Option 2: C= 8.50x	<BR>\n" );
document.write( "b)	How many hours would you have to rent the court so the monthly cost of option 1 is less than option 2? Set up an inequality and show your work algebraically using the information in part a.<BR>\n" );
document.write( "Answer:<BR>\n" );
document.write( "		Show your work here:\r<BR>\n" );
document.write( "\n" );
document.write( "I try to solve for question a. where it asks me about option one C= and for Option two C=, but i have no idea if its correct.  I dont know how to do the question b. Can someone help me and show me how to do this problem.  My homework is due sunday at 9:59 California time.  PLEASE!!!!!<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #154127 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=154127\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> option 1 = 42 + 5*h<BR>\n" );
document.write( "option 2 = 8.5*h<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "you want to know when option 1 < option 2.<BR>\n" );
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document.write( "your inequality equation would be:<BR>\n" );
document.write( "42 + 5*h < 8.5*h<BR>\n" );
document.write( "you subtract 5*h from both sides of the equation to get:<BR>\n" );
document.write( "42 < 8.5*h - 5*h<BR>\n" );
document.write( "you factor out the h on the right side of the equation to get:<BR>\n" );
document.write( "42 < (8.5-5)*h<BR>\n" );
document.write( "you simplify the right hand side of the equation to get:<BR>\n" );
document.write( "42 < 3.5*h<BR>\n" );
document.write( "you divide both sides of the equation by 3.5 to get:<BR>\n" );
document.write( "42/3.5 < h<BR>\n" );
document.write( "you simplify the left side of the equation to get:<BR>\n" );
document.write( "12 < h<BR>\n" );
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document.write( "12 < h is the same as h > 12<BR>\n" );
document.write( "here's how you would derive it if you're not familiar with how to do it.<BR>\n" );
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document.write( "start with 12 < h<BR>\n" );
document.write( "subtract 12 from both sides of the equation to get:<BR>\n" );
document.write( "0 < h - 12<BR>\n" );
document.write( "subtract h from both sides of the equation to get:<BR>\n" );
document.write( "-h < -12<BR>\n" );
document.write( "multiply both sides of the equation by -1 to get:<BR>\n" );
document.write( "h > 12<BR>\n" );
document.write( "note that multiplying both sides of an inequality by -1 reverses the inequality.<BR>\n" );
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document.write( "your answer is h > 12<BR>\n" );
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document.write( "option 1 will be cheaper than option 2 when h > 12<BR>\n" );
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document.write( "as a test, take h = 13<BR>\n" );
document.write( "option 1 = 42 + 5*13 = 42 + 65 = 107<BR>\n" );
document.write( "option 2 = 8.5*13 = 110.5<BR>\n" );
document.write( "option 1 is cheaper.<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "your break even point is at h = 12<BR>\n" );
document.write( "that's when option 1 equation equals option 2 equation which is when:<BR>\n" );
document.write( "42 + 5*h = 8.5*h<BR>\n" );
document.write( "to get the break even point you have to solve the equality equation.;<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "a graph of the equations looks like this.<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28600%2C600%2C-1%2C15%2C-10%2C200%2C1000000%2F%28x-12%29%2C42%2B5%2Ax%2C8.5%2Ax%29 ALIGN=MIDDLE  ALT=\"graph%28600%2C600%2C-1%2C15%2C-10%2C200%2C1000000%2F%28x-12%29%2C42%2B5%2Ax%2C8.5%2Ax%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "-----<BR>\n" );
document.write( "the line that crosses the y axis at 42 when h = 0 is your option 1 line.<BR>\n" );
document.write( "the line that crosses the origin is your option 2 line.<BR>\n" );
document.write( "the vertical line is when h = 12.<BR>\n" );
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document.write( "when h is smaller than 12, option 1 is more expensive.  when h = 12, both options are the same.  when h > 12 option 1 is cheaper.<BR>\n" );
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document.write( "the equations i used are:<BR>\n" );
document.write( "42 + 5*h<BR>\n" );
document.write( "8.5*h<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "i did, however, had to change h to x in order to allow them to be graphed.<BR>\n" );
document.write( "the equations for graphing purposes were:<BR>\n" );
document.write( "42 + 5*x<BR>\n" );
document.write( "8.5*x<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "for your purposes, just change all occurrences of h to x and you will have your equations in terms of x.<BR>\n" );
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