document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=204156>Question 204156</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the problem. Use 3.14 for &#960;. Round to the nearest tenth, if necessary.\r<BR>\n" );
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document.write( "A cylindrical drain pipe is 6 in. across the top and about 12 in. high. How many cubic inches of water could it hold?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #154110 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=154110\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The volume of a cylinder is<BR>\n" );
document.write( "V = pi*r^2*h, which is the cross-sectional area times the height.<BR>\n" );
document.write( "V = 3.14*3^2*12<BR>\n" );
document.write( "V = 3.14*9*12<BR>\n" );
document.write( "V = ~ 339.12 cubic inches </SPAN>\n" );
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