document.write( "Question 204110: A hare is 30 meters in front of a hound., and he runs 3 meters while the hound runs 6 meters, how many meters must the hound run to catch the hare? \n" ); document.write( "

Algebra.Com's Answer #154053 by RAY100(1637) $\"\"$ $\"About$

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let n= intervals, periods of time
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\n" ); document.write( "6n = 30 +3n,,,,,hound runs 6 / interval,,hare runs 3/ interval but has 30 head start
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\n" ); document.write( "3n =30
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\n" ); document.write( "n=10
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\n" ); document.write( "therefore hound runs,,,10*6=60
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\n" ); document.write( "hare runs 10*3 = 30,,,plus head start of 30 = 60
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